D\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n b\u1eafc h\u00f4m nay, c\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1 ch\u00ednh x\u00e1c b\u00e1 \u0111\u1ea1o nh\u1ea5t hi\u1ec7n nay.<\/h1>\n<\/div>\n\n<\/div>\n<\/div>\n<\/div>\nV\u1edbi m\u1ed7i. Anh em soi. C\u1ea7u l\u00f4<\/strong><\/em> x\u1ed5 s\u1ed1. Mi\u1ec1n b\u1eafc, th\u00ec vi\u1ec7c. D\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1. Mi\u1ec1n b\u1eafc h\u00f4m nay \u0111\u1ec3 cho ra nh\u1eefng. Con s\u1ed1 ch\u00ednh x\u00e1c. Nh\u1ea5t v\u00e0 th\u1eafng l\u1edbn. L\u00e0 m\u1ed9t \u0111i\u1ec1u kh\u00f4ng h\u1ec1. D\u1ec5 d\u00e0ng, kh\u00f4ng ai l\u00e0. Kh\u00f4ng th\u00edch v\u1eeba. Vui l\u1ea1i v\u1eeba c\u00f3. Ti\u1ec1n ph\u1ea3i kh\u00f4ng n\u00e0o?
\nD\u01b0\u01a1i \u0111\u00e2y l\u00e0 nh\u1eefng. Th\u00f4ng tin m\u00e0 anh em kh\u00f4ng. N\u00ean ch\u1ec9 \u0111\u1ecdc l\u01b0\u1edbt. Qua r\u1ed3i c\u01b0\u1eddi. Tr\u1eeb \u0111\u1ec3 r\u1ed3i b\u1ecf. Qua nh\u1eefng c\u01a1 h\u1ed9i. Chi\u1ebfn th\u1eb1ng d\u00f9 ch\u1ec9. L\u00e0 r\u1ea5t nh\u1ecf.<\/p>\n<\/p>\n
1. \u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c \u0111\u1ec3 tr\u00fang c\u1ea7u l\u00f4:<\/strong><\/p>\n\u0110\u00e2y l\u00e0 m\u1ed9t c\u00f4ng th\u1ee9c. Ph\u1ea3i n\u00f3i l\u00e0 r\u1ea5t hi\u1ec7u. Qu\u1ea3 v\u00e0 cho t\u1edbi th\u1eddi. \u0110i\u1ec3m hi\u1ec7n nay n\u00f3. V\u1eabn \u0111ang c\u00f2n h\u1eefu d\u1ee5ng, nhi\u1ec1u anh em \u0111\u00e3 cho l\u00e0 n\u00f3 v\u00f4 d\u1ee5ng nh\u01b0ng c\u00f3 l\u1ebd c\u00e1c anh em \u0111\u00f3. C\u00f3 th\u1ec3 \u0111\u00e3 \u00e1p d\u1ee5ng sai. V\u00e0 kh\u00f4ng v\u1eadn d\u1ee5ng. M\u1ed9t c\u00e1ch hi\u1ec7u qu\u1ea3, anh em kh\u00f4ng. N\u00ean d\u1eadp khu\u00f4n m\u1ed9t c\u00e1ch. M\u00e1y m\u00f3c m\u00e0 h\u00e3y. V\u1eadn d\u1ee5ng c\u00e1ch t\u00ednh l\u00f4 chu\u1ea9n<\/em><\/strong> m\u1ed9t c\u00e1ch hi\u1ec7u qu\u1ea3 nh\u00e9.
\n\u2013 C\u00f4ng th\u1ee9c n\u00e0y l\u00e0 \u00e1p d\u1ee5ng k\u1ebft qu\u1ea3. \u0110\u1eb7c bi\u1ec7t l\u00e0 s\u1ed1 \u0111\u1ec1 2 ng\u00e0y. Tr\u01b0\u1edbc \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y h\u00f4m nay b\u1eb1ng c\u00e1ch c\u1ed9ng. T\u1ed5ng s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb v\u1edbi h\u00e0ng ch\u1ee5c c\u00f9ng. M\u1ed9t s\u1ed1 b\u1ea5t k\u1ef3 \u0111\u1ec3 ra t\u1ed5ng. Ch\u1eb5n 10 v\u00e0 ch\u1eb5n 20. Nghe r\u1ea5t ph\u1ee9c. T\u1ea1p ph\u1ea3i kh\u00f4ng \u1ea1, sau \u0111\u00e2y. Ch\u00fang t\u00f4i \u0111\u01b0a ra c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\nC\u1ee5 th\u1ec3 nh\u01b0 sau: G\u1ecdi k\u1ebft qu\u1ea3 \u0111\u1ec1 c\u1ee7a 2 ng\u00e0y tr\u01b0\u1edbc \u0111\u00f3 l\u1ea7n l\u01b0\u1ee3t l\u00e0 AB v\u00e0 CD ta c\u00f3:<\/p>\n
A + B + X = 10 (ho\u1eb7c 20)<\/p>\n
C + D + Y = 20 (ho\u1eb7c 20)<\/p>\n
Nh\u01b0 v\u1eady \u0111\u00e1nh l\u00f4 XY cho ng\u00e0y th\u1ee9 3.<\/p>\n
-Anh em h\u1ebft s\u1ee9c l\u01b0u \u00fd khi \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c n\u00e0y:<\/p>\n
+Th\u00f4ng th\u01b0\u1eddng c\u1ea7u n\u00e0y v\u1ec1 t\u1eeb 3 \u0111\u1ebfn 4 ng\u00e0y, tuy nhi\u00ean s\u1ebd c\u00f3 \u0111\u1ee3t ch\u1ec9 v\u1ec1 1, 2 ng\u00e0y th\u00f4i v\u00ec v\u1eady n\u1ebfu g\u00e3y c\u1ea7u anh em h\u00e3y ngh\u1ec9 ng\u1eddi v\u00e0i h\u00f4m kh\u00f4ng theo c\u1ea7u n\u1eefa, t\u00ednh t\u1edbi ng\u00e0y h\u00f4m n\u00e0o c\u1ea7u v\u1ec1 th\u00ec theo l\u1ea1i, ch\u1edb c\u00f3 ham m\u00e0 theo li\u1ec1u anh em \u1ea1.
\n+ Trong tr\u01b0\u1eddng h\u1ee3p n\u1ebfu ch\u1ed1t XY v\u00e0 l\u1ea1i v\u1ec1 ng\u01b0\u1ee3c YX th\u00ec anh em h\u00e3y d\u1eebng l\u1ea1i \u0111\u1ee3i ch\u1edd 3, t\u1edbi 3 h\u00f4m sau theo l\u1ea1i nh\u00e9, \u0111\u1ee3i ch\u1edd l\u00e0 h\u1ea1nh ph\u00fac m\u00e0 l\u1ea1i.
\nM\u1ed9t v\u00ed d\u1ee5 c\u1ee5 th\u1ec3 cho anh em d\u1ec5 h\u00ecnh dung, c\u1ee9 X, Y m\u00e3i h\u1ea1i n\u00e3o ?<\/p>\n
Ng\u00e0y 15\/6\/2024 ta th\u1ea5y \u0111\u1ec1 v\u1ec1 45, ng\u00e0y 16 \u0111\u1ec1 v\u1ec1 48, Ap d\u1ee5ng theo c\u00f4ng th\u1ee9c ta c\u00f3:<\/p>\n
4 + 5 + 1 = 10<\/p>\n
4 + 8 + 8 = 20<\/p>\n
Nh\u01b0 v\u1eady ta s\u1ebd \u0111\u01b0\u1ee3c XY=18, \u0111em 18 \u0111\u00e1nh cho ng\u00e0y 17\/6\/2024 ta th\u1ea5y ng\u00e0y h\u00f4m \u0111\u00f3 kqxsmb ra 81 \u1edf gi\u1ea3i 7.
\nAnh em ch\u00fa \u00fd nh\u00e9, XY kh\u00f4ng ph\u1ea3i YX nh\u00e9, ta th\u1ea5y l\u1ed9n YX v\u00ec v\u1eady anh em ngh\u1ec9 3 t\u1edbi 4 h\u00f4m nh\u00e9.<\/p>\n
\u0110\u1ecdc qua th\u1ea5y ph\u1ee9c t\u1ea1p nh\u01b0ng \u00e1p d\u1ee5ng c\u0169ng th\u1ea5y \u0111\u01a1n gi\u1ea3n ph\u1ea3i kh\u00f4ng anh em.<\/p>\n
2. Soi c\u1ea7u l\u00f4 mi\u1ec1n b\u1eafc qua gi\u1ea3i 3 huy\u1ec1n tho\u1ea1i:<\/strong><\/p>\nSoi c\u1ea7u qua gi\u1ea3i 3 c\u00f3 th\u1ec3 n\u00f3i l\u00e0 c\u00e1ch \u0111\u00e1nh huy\u1ec1n tho\u1ea1i \u0111\u00e3 c\u00f3 t\u1eeb h\u00e0ng ch\u1ee5c n\u0103m nay, \u0111\u00e3 c\u00f3 r\u1ea5t nhi\u1ec1u anh em \u0103n lai lai c\u00e1ch ch\u01a1i n\u00e0y.<\/p>\n
<\/p>\n
V\u1eady c\u00e1ch \u0111\u00e1nh c\u1ea7u l\u00f4 n\u00e0y nh\u01b0 th\u1ebf n\u00e0o? H\u00e3y xem c\u1ee5 th\u1ec3 d\u01b0\u1edbi \u0111\u00e2y nh\u00e9:
\nN\u1ebfu anh em \u0111\u1ec3 \u00fd k\u1ef9 th\u00ec gi\u1ea3i 3 lu\u00f4n c\u00f3 m\u1ed9t c\u1ea7u \u0103n b\u00f3ng cho \u0111\u1ec1 ng\u00e0y ti\u1ebfp theo, ta s\u1ebd c\u00f3 2 d\u00e3y b\u00f3ng m D\u01b0\u01a1ng nh\u01b0 sau:
\nB\u00f3ng D\u01b0\u01a1ng c\u1ee7a c\u00e1c con s\u1ed1: 0-5; 1-6; 2-7; 3-8; 4-9 (v\u00e0 ng\u01b0\u1ee3c l\u1ea1i)
\nB\u00f3ng m c\u1ee7a c\u00e1c con s\u1ed1: 0-7; 1-4; 2-9; 3-6; 5-8 (v\u00e0 ng\u01b0\u1ee3c l\u1ea1i)<\/p>\n
3. \u0110\u00e1nh c\u1ea7u l\u00f4 mi\u1ec1n b\u1eafc theo gi\u1ea3i 5:
\nCh\u00fang ta l\u1ea5y t\u1ea5t c\u1ea3 nh\u1eefng s\u1ed1 \u0111\u1ea7u ti\u00ean c\u1ee7a c\u00e1c gi\u1ea3i 5 gh\u00e9p l\u1ea1i v\u1edbi c\u00e1c ch\u1ea1m c\u1ee7a gi\u1ea3i 5\/3 l\u00e0m d\u00e0n \u0111\u1ec1 \u0111\u00e1nh cho ng\u00e0y h\u00f4m sau:<\/p>\n
V\u00ed d\u1ee5 c\u1ee5 th\u1ec3:
\nK\u1ebft qu\u1ea3 xsmb ng\u00e0y 20\/7\/2024 ta c\u00f3 k\u1ebft qu\u1ea3 gi\u1ea3i 5 l\u00e0: 2517 9914 6555 8403 0104 4631
\nTa s\u1ebd th\u1ed1ng k\u00ea ra v\u00e0 c\u00f3 c\u00e1c s\u1ed1 \u0111\u1ea7u gh\u00e9p l\u1ea1i l\u00e0 296804 gh\u00e9p v\u1edbi ch\u1ea1m 5.3 l\u00e0 6555 ta c\u00f3 d\u00e0n
\n262 252 252 252
\n969 959 959 959
\n666 656 656 656
\n868 858 858 858
\n060 050 050 050
\n464 454 454 454
\nt\u1eeb d\u00e3y s\u1ed1 tr\u00ean ta c\u00f3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n b\u1eafc<\/strong><\/em> v\u1edbi b\u1ed9 s\u1ed1 sau:
\n26, 25, 69, 59, 68, 60, 05, 85, 64, 54<\/p>\nSang kqxsmb ng\u00e0y 21\/7\/2024 ta th\u1ea5y c\u00f3 \u0111\u1ec1 68 \u1edf trong d\u00e0n tr\u00ean, ngo\u00e0i ra c\u00f3 c\u00e1c l\u00f4: 26, 60,85.<\/p>\n
R\u1ea5t \u1ed5n ph\u1ea3i kh\u00f4ng n\u00e0o ?<\/p>\n
4. Soi c\u1ea7u l\u00f4 b\u1eb1ng \u0111\u1ea7u \u0111u\u00f4i:<\/strong><\/p>\nC\u00e1ch soi c\u1ea7u l\u00f4 mi\u1ec1n b\u1eafc n\u00e0y b\u1eb1ng \u0111\u1ea7u \u0111u\u00f4i th\u1eadt ra c\u0169ng r\u1ea5t \u0111\u01a1n gi\u1ea3n, anh em ch\u1ec9 c\u1ea7n \u0111\u1ec3 \u00fd h\u00f4m n\u00e0o c\u00f3 s\u1ed1 0 \u1edf gi\u1ea3i \u0111\u1eb7c bi\u1ec7t n\u1eb1m ch\u00ednh gi\u1eefa, th\u00ec ch\u1eafc ch\u1eafn nh\u1eefng ng\u00e0y t\u1edbi s\u1ebd v\u1ec1 \u0111\u1ea7u 0 ho\u1eb7c \u0111u\u00f4i 0.<\/p>\n
<\/p>\n
L\u1eddi k\u1ebft:<\/strong>
\nB\u00e0i vi\u1ebft tr\u00ean ch\u00fang t\u00f4i \u0111\u00e3 ch\u1eaft l\u1ecdc k\u1ef9 c\u00e0ng v\u00e0 ki\u1ec3m ch\u1ee9ng qua k\u1ebft qu\u1ea3 th\u1ef1c t\u1ebf, ph\u1ea3i n\u00f3i l\u00e0 t\u1edbi b\u00e2y gi\u1edd v\u1eabn \u0111ang c\u00f2n hi\u1ec7u qu\u1ea3, v\u1edbi nh\u1eefng anh em n\u00e0o ch\u01b0a bi\u1ebft c\u00e1ch soi c\u1ea7u mb<\/strong><\/em> \u1edf tr\u00ean th\u00ec \u0111\u00e2y l\u00e0 m\u1ed9t th\u00f4ng tin r\u1ea5t h\u1eefu \u00edch kh\u00f4ng th\u1ec3 b\u1ecf qua. V\u00e0 ch\u00fang t\u00f4i \u0111ang con r\u1ea5t nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p b\u00ec quy\u1ebft hay kh\u00e1c m\u00e0 ch\u1ec9 c\u00f3 tr\u00ean k\u1ebft qu\u1ea3 ba mi\u1ec1n, anh em h\u00e3y ch\u00fa \u00fd theo d\u00f5i website c\u1ee7a ch\u00fang t\u00f4i th\u01b0\u1eddng xuy\u00ean \u0111\u1ec3 n\u1eafm b\u1eaft \u0111\u01b0\u1ee3c nh\u01b0ng th\u00f4ng tin c\u1eadp nh\u1eadt m\u1edbi nh\u1ea5t nh\u00e9.<\/p>\n
V\u1edbi m\u1ed7i. Anh em soi. C\u1ea7u l\u00f4<\/strong><\/em> x\u1ed5 s\u1ed1. Mi\u1ec1n b\u1eafc, th\u00ec vi\u1ec7c. D\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1. Mi\u1ec1n b\u1eafc h\u00f4m nay \u0111\u1ec3 cho ra nh\u1eefng. Con s\u1ed1 ch\u00ednh x\u00e1c. Nh\u1ea5t v\u00e0 th\u1eafng l\u1edbn. L\u00e0 m\u1ed9t \u0111i\u1ec1u kh\u00f4ng h\u1ec1. D\u1ec5 d\u00e0ng, kh\u00f4ng ai l\u00e0. Kh\u00f4ng th\u00edch v\u1eeba. Vui l\u1ea1i v\u1eeba c\u00f3. Ti\u1ec1n ph\u1ea3i kh\u00f4ng n\u00e0o? <\/p>\n 1. \u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c \u0111\u1ec3 tr\u00fang c\u1ea7u l\u00f4:<\/strong><\/p>\n \u0110\u00e2y l\u00e0 m\u1ed9t c\u00f4ng th\u1ee9c. Ph\u1ea3i n\u00f3i l\u00e0 r\u1ea5t hi\u1ec7u. Qu\u1ea3 v\u00e0 cho t\u1edbi th\u1eddi. \u0110i\u1ec3m hi\u1ec7n nay n\u00f3. V\u1eabn \u0111ang c\u00f2n h\u1eefu d\u1ee5ng, nhi\u1ec1u anh em \u0111\u00e3 cho l\u00e0 n\u00f3 v\u00f4 d\u1ee5ng nh\u01b0ng c\u00f3 l\u1ebd c\u00e1c anh em \u0111\u00f3. C\u00f3 th\u1ec3 \u0111\u00e3 \u00e1p d\u1ee5ng sai. V\u00e0 kh\u00f4ng v\u1eadn d\u1ee5ng. M\u1ed9t c\u00e1ch hi\u1ec7u qu\u1ea3, anh em kh\u00f4ng. N\u00ean d\u1eadp khu\u00f4n m\u1ed9t c\u00e1ch. M\u00e1y m\u00f3c m\u00e0 h\u00e3y. V\u1eadn d\u1ee5ng c\u00e1ch t\u00ednh l\u00f4 chu\u1ea9n<\/em><\/strong> m\u1ed9t c\u00e1ch hi\u1ec7u qu\u1ea3 nh\u00e9. C\u1ee5 th\u1ec3 nh\u01b0 sau: G\u1ecdi k\u1ebft qu\u1ea3 \u0111\u1ec1 c\u1ee7a 2 ng\u00e0y tr\u01b0\u1edbc \u0111\u00f3 l\u1ea7n l\u01b0\u1ee3t l\u00e0 AB v\u00e0 CD ta c\u00f3:<\/p>\n A + B + X = 10 (ho\u1eb7c 20)<\/p>\n C + D + Y = 20 (ho\u1eb7c 20)<\/p>\n Nh\u01b0 v\u1eady \u0111\u00e1nh l\u00f4 XY cho ng\u00e0y th\u1ee9 3.<\/p>\n -Anh em h\u1ebft s\u1ee9c l\u01b0u \u00fd khi \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c n\u00e0y:<\/p>\n +Th\u00f4ng th\u01b0\u1eddng c\u1ea7u n\u00e0y v\u1ec1 t\u1eeb 3 \u0111\u1ebfn 4 ng\u00e0y, tuy nhi\u00ean s\u1ebd c\u00f3 \u0111\u1ee3t ch\u1ec9 v\u1ec1 1, 2 ng\u00e0y th\u00f4i v\u00ec v\u1eady n\u1ebfu g\u00e3y c\u1ea7u anh em h\u00e3y ngh\u1ec9 ng\u1eddi v\u00e0i h\u00f4m kh\u00f4ng theo c\u1ea7u n\u1eefa, t\u00ednh t\u1edbi ng\u00e0y h\u00f4m n\u00e0o c\u1ea7u v\u1ec1 th\u00ec theo l\u1ea1i, ch\u1edb c\u00f3 ham m\u00e0 theo li\u1ec1u anh em \u1ea1. Ng\u00e0y 15\/6\/2024 ta th\u1ea5y \u0111\u1ec1 v\u1ec1 45, ng\u00e0y 16 \u0111\u1ec1 v\u1ec1 48, Ap d\u1ee5ng theo c\u00f4ng th\u1ee9c ta c\u00f3:<\/p>\n 4 + 5 + 1 = 10<\/p>\n 4 + 8 + 8 = 20<\/p>\n Nh\u01b0 v\u1eady ta s\u1ebd \u0111\u01b0\u1ee3c XY=18, \u0111em 18 \u0111\u00e1nh cho ng\u00e0y 17\/6\/2024 ta th\u1ea5y ng\u00e0y h\u00f4m \u0111\u00f3 kqxsmb ra 81 \u1edf gi\u1ea3i 7. \u0110\u1ecdc qua th\u1ea5y ph\u1ee9c t\u1ea1p nh\u01b0ng \u00e1p d\u1ee5ng c\u0169ng th\u1ea5y \u0111\u01a1n gi\u1ea3n ph\u1ea3i kh\u00f4ng anh em.<\/p>\n 2. Soi c\u1ea7u l\u00f4 mi\u1ec1n b\u1eafc qua gi\u1ea3i 3 huy\u1ec1n tho\u1ea1i:<\/strong><\/p>\n Soi c\u1ea7u qua gi\u1ea3i 3 c\u00f3 th\u1ec3 n\u00f3i l\u00e0 c\u00e1ch \u0111\u00e1nh huy\u1ec1n tho\u1ea1i \u0111\u00e3 c\u00f3 t\u1eeb h\u00e0ng ch\u1ee5c n\u0103m nay, \u0111\u00e3 c\u00f3 r\u1ea5t nhi\u1ec1u anh em \u0103n lai lai c\u00e1ch ch\u01a1i n\u00e0y.<\/p>\n <\/p>\n V\u1eady c\u00e1ch \u0111\u00e1nh c\u1ea7u l\u00f4 n\u00e0y nh\u01b0 th\u1ebf n\u00e0o? H\u00e3y xem c\u1ee5 th\u1ec3 d\u01b0\u1edbi \u0111\u00e2y nh\u00e9: 3. \u0110\u00e1nh c\u1ea7u l\u00f4 mi\u1ec1n b\u1eafc theo gi\u1ea3i 5: V\u00ed d\u1ee5 c\u1ee5 th\u1ec3: Sang kqxsmb ng\u00e0y 21\/7\/2024 ta th\u1ea5y c\u00f3 \u0111\u1ec1 68 \u1edf trong d\u00e0n tr\u00ean, ngo\u00e0i ra c\u00f3 c\u00e1c l\u00f4: 26, 60,85.<\/p>\n R\u1ea5t \u1ed5n ph\u1ea3i kh\u00f4ng n\u00e0o ?<\/p>\n 4. Soi c\u1ea7u l\u00f4 b\u1eb1ng \u0111\u1ea7u \u0111u\u00f4i:<\/strong><\/p>\n C\u00e1ch soi c\u1ea7u l\u00f4 mi\u1ec1n b\u1eafc n\u00e0y b\u1eb1ng \u0111\u1ea7u \u0111u\u00f4i th\u1eadt ra c\u0169ng r\u1ea5t \u0111\u01a1n gi\u1ea3n, anh em ch\u1ec9 c\u1ea7n \u0111\u1ec3 \u00fd h\u00f4m n\u00e0o c\u00f3 s\u1ed1 0 \u1edf gi\u1ea3i \u0111\u1eb7c bi\u1ec7t n\u1eb1m ch\u00ednh gi\u1eefa, th\u00ec ch\u1eafc ch\u1eafn nh\u1eefng ng\u00e0y t\u1edbi s\u1ebd v\u1ec1 \u0111\u1ea7u 0 ho\u1eb7c \u0111u\u00f4i 0.<\/p>\n <\/p>\n L\u1eddi k\u1ebft:<\/strong>
\nD\u01b0\u01a1i \u0111\u00e2y l\u00e0 nh\u1eefng. Th\u00f4ng tin m\u00e0 anh em kh\u00f4ng. N\u00ean ch\u1ec9 \u0111\u1ecdc l\u01b0\u1edbt. Qua r\u1ed3i c\u01b0\u1eddi. Tr\u1eeb \u0111\u1ec3 r\u1ed3i b\u1ecf. Qua nh\u1eefng c\u01a1 h\u1ed9i. Chi\u1ebfn th\u1eb1ng d\u00f9 ch\u1ec9. L\u00e0 r\u1ea5t nh\u1ecf.<\/p>\n
\n\u2013 C\u00f4ng th\u1ee9c n\u00e0y l\u00e0 \u00e1p d\u1ee5ng k\u1ebft qu\u1ea3. \u0110\u1eb7c bi\u1ec7t l\u00e0 s\u1ed1 \u0111\u1ec1 2 ng\u00e0y. Tr\u01b0\u1edbc \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y h\u00f4m nay b\u1eb1ng c\u00e1ch c\u1ed9ng. T\u1ed5ng s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb v\u1edbi h\u00e0ng ch\u1ee5c c\u00f9ng. M\u1ed9t s\u1ed1 b\u1ea5t k\u1ef3 \u0111\u1ec3 ra t\u1ed5ng. Ch\u1eb5n 10 v\u00e0 ch\u1eb5n 20. Nghe r\u1ea5t ph\u1ee9c. T\u1ea1p ph\u1ea3i kh\u00f4ng \u1ea1, sau \u0111\u00e2y. Ch\u00fang t\u00f4i \u0111\u01b0a ra c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\n+ Trong tr\u01b0\u1eddng h\u1ee3p n\u1ebfu ch\u1ed1t XY v\u00e0 l\u1ea1i v\u1ec1 ng\u01b0\u1ee3c YX th\u00ec anh em h\u00e3y d\u1eebng l\u1ea1i \u0111\u1ee3i ch\u1edd 3, t\u1edbi 3 h\u00f4m sau theo l\u1ea1i nh\u00e9, \u0111\u1ee3i ch\u1edd l\u00e0 h\u1ea1nh ph\u00fac m\u00e0 l\u1ea1i.
\nM\u1ed9t v\u00ed d\u1ee5 c\u1ee5 th\u1ec3 cho anh em d\u1ec5 h\u00ecnh dung, c\u1ee9 X, Y m\u00e3i h\u1ea1i n\u00e3o ?<\/p>\n
\nAnh em ch\u00fa \u00fd nh\u00e9, XY kh\u00f4ng ph\u1ea3i YX nh\u00e9, ta th\u1ea5y l\u1ed9n YX v\u00ec v\u1eady anh em ngh\u1ec9 3 t\u1edbi 4 h\u00f4m nh\u00e9.<\/p>\n
\nN\u1ebfu anh em \u0111\u1ec3 \u00fd k\u1ef9 th\u00ec gi\u1ea3i 3 lu\u00f4n c\u00f3 m\u1ed9t c\u1ea7u \u0103n b\u00f3ng cho \u0111\u1ec1 ng\u00e0y ti\u1ebfp theo, ta s\u1ebd c\u00f3 2 d\u00e3y b\u00f3ng m D\u01b0\u01a1ng nh\u01b0 sau:
\nB\u00f3ng D\u01b0\u01a1ng c\u1ee7a c\u00e1c con s\u1ed1: 0-5; 1-6; 2-7; 3-8; 4-9 (v\u00e0 ng\u01b0\u1ee3c l\u1ea1i)
\nB\u00f3ng m c\u1ee7a c\u00e1c con s\u1ed1: 0-7; 1-4; 2-9; 3-6; 5-8 (v\u00e0 ng\u01b0\u1ee3c l\u1ea1i)<\/p>\n
\nCh\u00fang ta l\u1ea5y t\u1ea5t c\u1ea3 nh\u1eefng s\u1ed1 \u0111\u1ea7u ti\u00ean c\u1ee7a c\u00e1c gi\u1ea3i 5 gh\u00e9p l\u1ea1i v\u1edbi c\u00e1c ch\u1ea1m c\u1ee7a gi\u1ea3i 5\/3 l\u00e0m d\u00e0n \u0111\u1ec1 \u0111\u00e1nh cho ng\u00e0y h\u00f4m sau:<\/p>\n
\nK\u1ebft qu\u1ea3 xsmb ng\u00e0y 20\/7\/2024 ta c\u00f3 k\u1ebft qu\u1ea3 gi\u1ea3i 5 l\u00e0: 2517 9914 6555 8403 0104 4631
\nTa s\u1ebd th\u1ed1ng k\u00ea ra v\u00e0 c\u00f3 c\u00e1c s\u1ed1 \u0111\u1ea7u gh\u00e9p l\u1ea1i l\u00e0 296804 gh\u00e9p v\u1edbi ch\u1ea1m 5.3 l\u00e0 6555 ta c\u00f3 d\u00e0n
\n262 252 252 252
\n969 959 959 959
\n666 656 656 656
\n868 858 858 858
\n060 050 050 050
\n464 454 454 454
\nt\u1eeb d\u00e3y s\u1ed1 tr\u00ean ta c\u00f3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n b\u1eafc<\/strong><\/em> v\u1edbi b\u1ed9 s\u1ed1 sau:
\n26, 25, 69, 59, 68, 60, 05, 85, 64, 54<\/p>\n
\nB\u00e0i vi\u1ebft tr\u00ean ch\u00fang t\u00f4i \u0111\u00e3 ch\u1eaft l\u1ecdc k\u1ef9 c\u00e0ng v\u00e0 ki\u1ec3m ch\u1ee9ng qua k\u1ebft qu\u1ea3 th\u1ef1c t\u1ebf, ph\u1ea3i n\u00f3i l\u00e0 t\u1edbi b\u00e2y gi\u1edd v\u1eabn \u0111ang c\u00f2n hi\u1ec7u qu\u1ea3, v\u1edbi nh\u1eefng anh em n\u00e0o ch\u01b0a bi\u1ebft c\u00e1ch soi c\u1ea7u mb<\/strong><\/em> \u1edf tr\u00ean th\u00ec \u0111\u00e2y l\u00e0 m\u1ed9t th\u00f4ng tin r\u1ea5t h\u1eefu \u00edch kh\u00f4ng th\u1ec3 b\u1ecf qua. V\u00e0 ch\u00fang t\u00f4i \u0111ang con r\u1ea5t nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p b\u00ec quy\u1ebft hay kh\u00e1c m\u00e0 ch\u1ec9 c\u00f3 tr\u00ean k\u1ebft qu\u1ea3 ba mi\u1ec1n, anh em h\u00e3y ch\u00fa \u00fd theo d\u00f5i website c\u1ee7a ch\u00fang t\u00f4i th\u01b0\u1eddng xuy\u00ean \u0111\u1ec3 n\u1eafm b\u1eaft \u0111\u01b0\u1ee3c nh\u01b0ng th\u00f4ng tin c\u1eadp nh\u1eadt m\u1edbi nh\u1ea5t nh\u00e9.<\/p>\n